Operating System Mcqs

Page No. 80

There is no __________ with linked allocation.


ainternal fragmentation

✖


bexternal fragmentation

✓


cstarvation

✖


dall of the mentioned

✖



In the linked allocation, the directory contains a pointer to which block?
I. first block
II. last block


aI only

✖


bII only

✖


cBoth I and II

✓


dNeither I nor II

✖


View Answer Both I and II

When in contiguous allocation the space cannot be extended easily?


athe contents of the file have to be copied to a new space, a larger hole

✓


bthe file gets destroyed

✖


cthe file will get formatted and lost all its data

✖


dnone of the mentioned

✖



During compaction time, other normal system operations _______ be permitted.


acan

✖


bcannot

✓


cis

✖


dnone of the mentioned

✖


View Answer cannot

For processes to request access to file contents, they need _____________


ato run a separate program

✖


bspecial interrupts

✖


cto implement the open and close system calls

✓


dnone of the mentioned

✖



For each file there exists a ___________ that contains information about the file, including ownership, permissions and location of the file contents.


ametadata

✖


bfile control block

✓


cprocess control block

✖


dall of the mentioned

✖


View Answer file control block

Metadata includes _____________


aall of the file system structure

✖


bcontents of files

✖


cboth file system structure and contents of files

✓


dnone of the mentioned

✖



The file organization module knows about _____________


afiles

✖


blogical blocks of files

✖


cphysical blocks of files

✖


dall of the mentioned

✓


View Answer all of the mentioned

A device driver can be thought of like a translator. Its input consists of _____ commands and output consists of _______ instructions.


ahigh level, low level

✓


blow level, high level

✖


ccomplex, simple

✖


dlow level, complex

✖


View Answer high level, low level

Consider a disk where blocks 2, 3, 4, 5, 8, 9, 10, 11, 12, 13, 17, 18, 25, 26 and 27 are free and the rest of the blocks are allocated. Then the free space bitmap would be _____________


a10000110000001110011111100011111…

✖


b110000110000001110011111100011111…

✖


c01111001111110001100000011100000…

✖


d001111001111110001100000011100000…

✓



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